Prove: An even times an even is
an even.
2n 2m [? ]mn
= even
=

Answer: 4nm
You'll need to take 2 * 2 separately which will equal 4
Then you need to n * m which is nm
Thus equaling
4nm
Answer:
2n × 2m = 4mn
Assume n = 1, m = 1
Step-by-step explanation:
[tex]2n \cdot 2m=\:?\\= \left(2 \cdot n\right) \cdot \left(2 \cdot m\right)\\= 2 \cdot 2\\= 4\\= 4mn\\\mathrm{Even}[/tex]
Hope this helps!