The de broglie wavelength is
[tex]λ = 1.921 \times 10 {}^{ - 36} m[/tex]
what is debroglie wavelength?
The deBroglie wavelength is defined as λ = h/mv , where the greek letter lambda represents the wavelength, h is Planck's contant, m is the particle's mass and v is its velocity.
E=
[tex] = \frac{m {}^{2} v {}^{2} }{2m} [/tex]
[tex] = \frac{(mv {}^{2}) }{2m} [/tex]
[tex] = \frac{p {}^{2} }{2m} [/tex]
λ=h/p
[tex]λ = \frac{h}{mv} [/tex]
[tex]λ = \frac{6.63 \times 10 {}^{ - 34} }{75kg \times 4.6 \frac{m}{s} } [/tex]
[tex]λ = 1.921 \times 10 {}^{ - 36} m[/tex]
Hence,the de broglie wavelength comes out to be
[tex] = 1.921 \times 10 { }^{ - 36} [/tex]
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