If Yumi takes 5/12 hour to complete 50 math problems Eric is able to complete 48 math problems in 2/5 hour the student that can complete math problems at a greater rate of problems per hour is: They solve the same number of problems per hour.
Calculation for the rate of Yumi
Yumi=5/12×60
Yumi=25 minutes
Rate=50/25
Rate=2
Calculation for the rate of Eric
Eric=2/5×60
Eric=24 minutes
Rate=48/24
Rate=2
Hence, Both Yumi and Eric has the same rate which is 2.
Therefore If Yumi takes 5/12 hour to complete 50 math problems Eric is able to complete 48 math problems in 2/5 hour the student that can complete math problems at a greater rate of problems per hour is: They solve the same number of problems per hour.
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