Given the point and slope, the equation of the line is in slope-intercept form is y = (-2/3)x + 2
What is the equation of line with the given point and slope?
The formula for equation of line is expressed as;
y = mx + b
Where m is slope and b is y-intercept.
Given the data in the question;
Point ( 9, -4 )
- x = 9
- y = -4
- Slope m = -2/3
Since already have the slope, we determine the y-intercept b by substituting the given values into the equation of line formula.
y = mx + b
-4 = (-2/3)9 + b
Solve for b
-4 = -18/3 + b
-4 = -6 + b
b = -4 + 6
b = 2
Now that the values of slope m and y-intercept b is known, plug these into y = mx + b to determine the equation of the line.
y = mx + b
y = (-2/3)x + 2
Given the point and slope, the equation of the line is in slope-intercept form is y = (-2/3)x + 2
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