what is the heat of a reaction, in joules, with a total reaction mixture volume of 67.9 ml if the reaction causes a temperature change of 6.5 oc in a calorimeter? assume that the reaction mixture has a density of 1.00 g/ml and a specific heat of 4.184 j/g-oc. the calorimeter has a heat capacity of 10.0 j/oc.

Respuesta :

The heat of reaction is  1.8 KJ.

How to calculate calorimeter?

Volume of water = 67.9 mL

Since the density of water is 1.00 g/mL

Density = mass/volume

Mass of water = Density × volume

Mass of water =  1 g/mL × 67.9 mL

Mass of water = 67.9g or 0.0679 Kg

Temperature change =  6.5 oC

Specific heat capacity of water= 4.184 J/Kg

From;

H = mcθ

m = mass of water

c = heat capacity of water

θ = temperature rise

Substituting values;

H = 0.0679 Kg × 4.184 J/Kg × 6.5 oC

H = 1.8 KJ

To learn more about calorimeter refer to:

https://brainly.com/question/1407669

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