We can use the formula of the capacitance
[tex]C=\frac{Q}{V}[/tex]where C is the capacitance, Q is the charge and V is the voltage.
In our case
Q=480 C
V= 110 V
[tex]C=\frac{480}{110}=4.36\text{ F}[/tex]The value of the capacitor is 4.36 F
ANSWER B) 4.36F