We can replace x=20000 in the function so:
[tex]c(20000)=15000+8(20000)-\frac{20000^2^{}}{20000}[/tex]and we simplify:
[tex]c(20000)=15500[/tex]now h=1 is the cost of one more item so we evaluate for 20001
[tex]\begin{gathered} c(20001)=15000+8(20001)-\frac{20001^2}{20000} \\ c(20001)=195010 \end{gathered}[/tex]So for h=1 will be :
[tex]C=0.599950[/tex]