Given:
[tex]\begin{gathered} x+2y\le6\ldots\text{ (1)} \\ 3x-4y<2\ldots(2) \end{gathered}[/tex]
We have to take the value of x as zero and to find the value of y in bothe the equations to plot the graph.
By taking the value of x as zero in the first equation,
[tex]\begin{gathered} 2y\le6 \\ y\le3 \end{gathered}[/tex]
By taking the value of y as zero in the first equation,
[tex]x\le6[/tex]
By taking the value of x as zero in the second equation,
[tex]\begin{gathered} -4y<2 \\ -2y<1 \\ y>-\frac{1}{2} \end{gathered}[/tex]
By taking the value of y as zero in the second equation,
[tex]\begin{gathered} 3x<2 \\ x<\frac{2}{3} \end{gathered}[/tex]
