Respuesta :
We have the following quadratic equation:
x - 16 x + 48
To factorize it, we need to find two integer numbers that:
A. Added together, the result will be equal to - 16
B. Mutiiplied together, the result will be equal to 48
Those numbers are - 12 and - 4:
A. - 12 + - 4 = -12 - 4 = - 16
B. -12 * -4 = - (-48) = 48
Now we can factorize, as follows:
Is x - 16 x + 48 or x2 - 16x + 48?
You don't answer, I will factorize both cases:
If the equation is x2 - 16x + 48, then the answer is:
(x - 12) (x -4) = 0 and the roots are:
[tex]x_{1_{\square}}=16,x_{2\text{ = 4 }}[/tex]If the equation is x - 16x + 48, then the answer is:
x - 16x + 48
-15x + 48
Dividing the coefficients by 3:
-5x + 16
-5x = -16
Dividing by -5:
-5x/-5 = -16/-5
x = 16/5
x = 3 1/5
