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a mixture contains only nacl and fe(no3)3. a 0.456 gram sample of the mixture is dissolved in water, and an excess of naoh is added, producing a precipitate of fe(oh)3. the precipitate is filtered, dried and weighed. its mass is 0.107 g. calculate the mass percent of fe(no3)3 in the sample.

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ecthyion

Answer:

0.23 mass percent

Explanation:

The molar mass of Fe(NO3)3 is 241.9 g/mol and the molar mass of NaCl is 58.5 g/mol. This means that for every 1 mol of Fe(NO3)3, there are 4.14 mol of NaCl. In a 0.456 gram sample, this would be 0.01098 moles or 109 mg of Fe(NO3)3 and 0.456 * (4.14 mol / 1 mol) = 1.892 grams or 1892 mg of NaCl

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