Question 23 Differentiate. f(x) = (5x - 5)(6x + 1) O f'(x) = 60x - 25 O f'(x) = 30x - 25 O f'(x) = 60x - 35 f'(x) = 60x - 12.5

We have to differentiate f(x).
We can do this as:
[tex]\begin{gathered} f(x)=(5x-5)(6x+1)=30x^2-30x+5x-5=30x^2-25x-5 \\ f\text{'}(x)=30\cdot(2x)-25\cdot(1)-0 \\ f\text{'}(x)=60x-25 \end{gathered}[/tex]The answer is f'(x)=60x-25.