Answer:
The number which can be multiplied to each term of the equation to eliminate the fractions is:
12
Step-by-step explanation:
We are given a equation:
[tex]6-\dfrac{3}{4}x+\dfrac{1}{3}=\dfrac{1}{2}x+5[/tex]
We see as we multiply both sides of the equation by 12 the fractions are eliminated and equation is transformed to:
72-9x+4=6x+60
Hence, the number which can be multiplied to each term of the equation to eliminate the fractions is:
12
