a 950n basketball player jumps to block a jump shot. here is what you know: the average force applied to the floor: 1800n force is applied over a vertical distance of .5m (from the lowest point in the squat to the position at the instant of takeoff.

Respuesta :

The instant take off speed is 2.96 m/s

What is force applied over distance?

  • It is intimately correlated with both the amount of force applied to the item and its motion. The equation below may be used to compute work: Work is equal to force times distance. The Newton meter is the SI unit of work (N m). When an item is moved across a distance of 1 m with 1 N of force, one joule is equal to the amount of work that is accomplished.
  • The forces and motion in a standing vertical leap are both vertical. F = FGRF - mg, where FGRF is the vertical ground reaction force applied to the jumper and mg is the jumper's body weight, results in a vertical force on the jumper.

Given :

Weight of the Basket ball Player = 950 N.

Force Applied on the Floor = 1800 N

over Vertical distance  = .5 m

resultant force f = 1800 N - 950 N = 850 N

work done = 850 * 0.5 m =425 J

kenetic energy = 1/2 mv^2= 425

mass = 950/ g = 96.9

v^2 = 425 * 2/ 96.9

v= [tex]\sqrt{8.78}[/tex] = 2.96 m/s

instant Take off is 2.96 m/s

To learn more about Work  refer,

https://brainly.com/question/25405393

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