Answer:
6.5v +0.5u
Step-by-step explanation:
You want to express ln(b^6.5·√a) in terms of u = ln(a) and v = ln(b).
The relevant rules of logarithms are ...
ln(ab) = ln(a)+ln(b)
ln(a^b) = b·ln(a)
The given logarithm can be rewritten as ...
ln(b^6.5·√a) = ln(b^6.5) +ln(a^0.5) = 6.5ln(b) +0.5ln(a)
= 6.5v +0.5u
