Respuesta :
we have [tex]f(n+1)=f(n)-2[/tex] with [tex]f(1)=18[/tex]
so
[tex]f(2)=f(1)-2=18-2=16,\\ f(3)=f(2)-2=14,\\ f(4)=f(3)-2=12,\\ f(5)=f(4)-2=10.[/tex]
Hence [tex]f(5)=10.[/tex]
so
[tex]f(2)=f(1)-2=18-2=16,\\ f(3)=f(2)-2=14,\\ f(4)=f(3)-2=12,\\ f(5)=f(4)-2=10.[/tex]
Hence [tex]f(5)=10.[/tex]
hello :
this is the arithmetic - sequence when the common diference is : d = -2
the general term is : f(n) =f(1) +(n-1)d .. d= -2 and f(1) =18
let : n= 5
f(5) = f(1) +(5-1)(-2)
f(5) = 18 -8 = 10
this is the arithmetic - sequence when the common diference is : d = -2
the general term is : f(n) =f(1) +(n-1)d .. d= -2 and f(1) =18
let : n= 5
f(5) = f(1) +(5-1)(-2)
f(5) = 18 -8 = 10