Answer:
[tex]\boxed{\Delta T = 3.58\°\text{C}}[/tex]
Explanation:
The specific heat of water is:
[tex]4.184 \text{ J}/[\text{g}\cdot \°C][/tex]
We can use this in the thermodynamics equation:
[tex]q=mc(\Delta T)[/tex]
where:
We are trying to solve for change in temperature. So, we can rearrange the equation to:
[tex]\Delta T = \dfrac{q}{mc}[/tex]
↓ plugging in the given values
[tex]\Delta T = \dfrac{(150.0 \ \text{J})}{(10.0 \text{ g})(4.184 \text{ J} / [\text{g} \cdot \°\text{C}])}[/tex]
↓ evaluating using a calculator
[tex]\boxed{\Delta T = 3.58\°\text{C}}[/tex]
