Answer:
[tex]\log(86)\approx1.9345[/tex]
Step-by-step explanation:
We can rewrite the given expression:
[tex]\log(86)[/tex]
using the multiplication property of logarithms:
[tex]\log(a\cdot b) = \log(a) + \log(b)[/tex]
↓↓↓
[tex]\log(86) = \log(2 \cdot 43) = \log(2) +\log(43)[/tex]
Then, we can plug in the given approximate values:
↓↓↓
[tex]\log(86) \approx 0.3010 + 1.6335[/tex]
[tex]\boxed{\log(86)\approx1.9345}[/tex]
