In a gas that is a mixture of water (two H and one O) and carbon dioxide (one C and two O), if the water has average velocity of 327 m/s, what is the average velocity of the carbon dioxide molecule? Give your answer as number in units of m/s without entering the units.

Respuesta :

Answer:

209 m/s

Explanation:

From ideal gas law, the root mean square velocity of the gas particles is:

v = √(3RT / M)

where R is the ideal gas constant,

T is absolute temperature,

and M is molar mass.

The molar mass of water H₂O is 2(1) + 1(16) = 18 g/mol = 0.018 kg/mol.

The molar mass of carbon dioxide CO₂ is 1(12) + 2(16) = 44 g/mol = 0.044 kg/mol.

The average speed of the water molecules is 327 m/s, so the temperature of the gas mixture is:

327 m/s = √(3 × 8.314 J/K/mol × T / (0.018 kg/mol))

T = 77.2 K

The average speed of the carbon dioxide molecules is therefore:

v = √(3 × 8.314 J/K/mol × 77.2 K / (0.044 kg/mol))

v = 209 m/s