Answer:
Object is 59.30m away from the base of the cliff
Step-by-step explanation:
In the figure attached, AB is a vertical cliff 40 m high, and the angle of depression is 34° of an object at the point O.
Since angle of depression is always equal to the angle of the elevation of the cliff from the object.
From Δ ABO,
tan34° = [tex]\frac{AB}{BO}[/tex]
0.6745 = [tex]\frac{40}{BO}[/tex]
BO×0.6745 = 40
BO = [tex]\frac{40}{0.6745}[/tex]
BO = 59.30 m
Therefore, object is 59.30m away from the base of the cliff .
