Respuesta :

WWFelina
Power in a circuit = V.I
30 = (120)(I)
I = 0.25 A
We know, current is the rate of flow of charge per unit time. This means 0.25 A corresponds to the flow of 0.25 C of charge every second.

That implies, in a minute 0.25 x 60 = 15 C of charge flows.
nuhulawal20

The quantity of charge flowing through the light bulb in the given time is 15 Coulombs.

Given the data in the question;

  • Power; [tex]p = 30W[/tex]
  • Voltage; [tex]V = 120v[/tex]
  • Time; [tex]t = 1.0min = 60s[/tex]

Quantity of Charge; [tex]Q = \ ?[/tex]

Power

Power can be simply defined as the quantity of energy converted or transferred per unit time. It can be expressed as;

[tex]P = V * I[/tex]

Where V is the Voltage and I is current.

Also as a rate quantity, current can be expressed;

[tex]I = \frac{Q}{t}[/tex]

Where I is current, Q is the quantity of charge flowing per unit time and t is time.

Now, we input our given values into the above expression to determine Current

[tex]P = V * I\\\\30W = 120v * I\\\\I = \frac{30W}{120v} \\\\I = 0.25A[/tex]

Next we calculate the quantity of charge flowing through the light bulb using the above expression.

[tex]I = \frac{Q}{t}\\ \\0.25A = \frac{Q}{60s} \\\\Q = 0.25A * 60s\\\\Q = 15C[/tex]

Therefore, the quantity of charge flowing through the light bulb in the given time is 15 Coulombs.

Learn more about Quantity of Charge: https://brainly.com/question/490562

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