A 300 kg dragster accelerates from the rest to the final speed of 120 m/s in 400 m (about a quarter of a mile) and encounters an average frictional force of 1200 N. What is the average output in watts AND horsepower if this takes 7.30 seconds?

Question

23-12-2017
Business

contestada

A 300 kg dragster accelerates from the rest to the final speed of 120 m/s in 400 m (about a quarter of a mile) and encounters an average frictional force of 1200 N. What is the average output in watts AND horsepower if this takes 7.30 seconds?

Respuesta :

Otras preguntas

Mr. Abernathy bought a selection of wrenches for his shop and paid $78. He bought the same number of $1.50 and $2.50 wrenches, and half of that number of $4 wre

The gravitational strength at the poles is greater than the gravitational strength at the equator. What will happen to an object when it moves from the poles to

Which elements has the same chemical and physical properties the one in the same period or the one the same group?

Three times the sum of a number and six is greater than four times the number decreased by two

List of presidents and political affinities

Answer the lab question (“what is the effect of temperature on the solubility of a solid in a liquid?”) with a hypothesis:

A sailboat is heading directly north at a speed of 20 knots (1 knot 50.514 m/s). the wind is blowing toward the east with a speed of 17 knots. (a) determine the

Question 1(Multiple Choice Worth 5 points) These lines from Kennedy's 1963 Civil Rights Address seek to most clearly define which idea? One hundred years of del

What is 265888 rounded to nearest ten thousands

How many numbers are 10 units from 0 on the number line?

carlosego carlosego · Answer 1 · 2017-12-31T17:40:49+01:00

Let P be the average power output. The total amount of work done is P*(7.3s)). But the total amount of work done is also the sum of these two quantities:
1._ The work done to overcome friction. 2._The kinetic energy of the dragster at the end of the 400 m. Then the first part of the work done is (1200N)*(400m)=480000 J.
Part 2 is given by the kinetic energy formula: 1/2*(300)*(120^2)=2160000 J.
Taken together, that's 2640000 J.
Divide by the time (7.3s) and you have average power output of about
361643.836 Watts and in HP is 361643.836/745.7=484.972289 HP