contestada

If the reaction of 3.75 moles of lithium with excess hydrofluoric acid produced a 96.5% yield of hydrogen gas, what was the actual yield of hydrogen gas? unbalanced equation: li + hfyields lif + h2

Respuesta :

1.81 mol H2. Hope this answer helped! 

Answer : The actual yield of hydrogen gas is, 3.618 grams

Explanation : Given,

Given moles of [tex]Li[/tex] = 3.75 moles

Molar mass of [tex]H_2[/tex] = 2 g/mole

Now we have to calculate the moles of [tex]H_2[/tex].

The balanced chemical reaction will be,

[tex]2Li+2HF\rightarrow 2LiF+H_2[/tex]

From the given balanced reaction, we conclude that

As, 2 moles of [tex]Li[/tex] react to give 1 mole of [tex]H_2[/tex]

So, 3.75 moles of [tex]Li[/tex] react to give [tex]\frac{3.75}{2}=1.875[/tex] moles of [tex]H_2[/tex]

Now we have to calculate the mass of [tex]H_2[/tex].

[tex]\text{Mass of }H_2=\text{Moles of }H_2\times \text{Molar mass of }H_2[/tex]

[tex]\text{Mass of }H_2=(1.875mole)\times (2g/mole)=3.75g[/tex]

The theoretical yield of [tex]H_2[/tex] is, 3.75 grams

Now we have to calculate the actual yield of [tex]H_2[/tex].

[tex]\%\text{ yield of }H_2=\frac{\text{Actual yield of }H_2}{\text{Theoretical yield of }H_2}\times 100[/tex]

[tex]96.5=\frac{\text{Actual yield of }H_2}{3.75g}\times 100[/tex]

[tex]\text{Actual yield of }H_2=3.618g[/tex]

Therefore, the actual yield of hydrogen gas is, 3.618 grams

Otras preguntas