For this case we have the following equations:
[tex] C = 24x + 80
R = 44x[/tex]
The break even point occur when C = R:
We have then:
[tex] 24x + 80 = 44x
[/tex]
Clearing x we have:
[tex] 44x - 24x = 80
20x = 80
x = 80/20
x = 4[/tex]
Then, substituting in any of the equations we have:
[tex] C = 24 (4) +80
C = 96 + 80
C = 176[/tex]
The break even point is:
(4, 176)
Answer:
The break even point is:
(4, 176)
