First of all we can draw a parallel line to divide the figure into a triangle and a rectangle as shown in the figure. To find the area of our rectangle, remember that the area of a rectangle is length times width, so [tex]A_{r} =lw[/tex]. Since we know for our figure that the length and width of our rectangle are 13cm and 6cm respectively, lets replace those values in our formula to get its area:
[tex]A _{r} =(13cm)(6cm)[/tex]
[tex]A=78cm^{2} [/tex]
Similarly, the area of a triangle is one half times base times height, so [tex]At=( \frac{1}{2})bh [/tex]. Since we know that our base is 8cm and our height 6cm, lets replace those values in our equation to find the area of our triangle:
[tex]A_{t} =( \frac{1}{2})(8cm)(6cm) [/tex]
[tex]A_{t} =24cm^{2} [/tex]
Now the only thing left is add our areas:
[tex]A_{total} =78cm^{2}+24cm^{2} =102cm^{2} [/tex]
We can conclude that the correct answer is A. 102
