In case 1, the torque is given by the product between the force and the arm:
[tex]\tau_1 = F \cdot \frac{L}{2} [/tex]
In case 2, the torque is given by the product between the component of the force perpendicular to the arm and the arm itself, so we have:
[tex]\tau_2 = F \cos 30^{\circ} L=F \frac{ \sqrt{3} }{2} L = \sqrt{3} F \frac{L}{2}= \sqrt{3} \tau_1 [/tex]
and since [tex] \sqrt{3} [/tex] is larger than 1, than the torque in case 2 is larger than the torque in case 1.
