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The perimeter of a rectangle is 256 inches. how long are the sides if the length exceeds the width by 16 inches? mark lets x represent the width of the rectangle and writes the equation 2x + 2(x + 16) = 256. solving for x, the width of the rectangle is 56 60 68

Respuesta :

crisforp
We have 2x + 2x + 32 = 256;
Then 4x + 32 = 256;
4x = 256-32;
4x = 224;
x = 224/4;
x = 56;
The width is 2·56 = 112 inches;
The length is 112 + 16 = 128 inches;

Answer:

X=56

Step-by-step explanation:

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