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a 12.0L container is filled with a gas to a pressure of 2660 torr at 0°C. At what temp. will the pressure inside the container be 3040 torr if volume is held constant?

Respuesta :

alleann02
[tex] \frac{p1}{t1} = \frac{p2}{t2} [/tex]

Pressure Law: constant volume

Convert all Temperatures to Kelvin

0°C= 273K

[tex] \frac{2660}{273} = \frac{3040}{t2} \\ \\ 3040 \times 273 = t2 \times 2660 \\ \\ 829920 \div 2660 = t2 \\ \\ t2 = 312[/tex]

answer= 312Kelvin

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