Answer:
(0, 3) lies on the line joining (2, -2) and (-4, 13).
Step-by-step explanation:
The equation of the line joining the points (2, -2) and (-4, 13) is:
[tex]\frac{y+2}{13+2} =\frac{x-2}{-4-2}[/tex]
[tex]\frac{y+2}{15} =\frac{x-2}{-6}[/tex]
[tex]\frac{y+2}{5} =\frac{x-2}{-2}[/tex]
-2(y + 2) = 5(x - 2)
-2y - 4 = 5x - 10
5x + 2y - 6 = 0
When we substitute x = 0 and y = 3,
5(0) + 2(3) = 0 + 6 = 6
So, (0, 3) lies on the line joining (2, -2) and (-4, 13).
