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The pressure of a gas with a pressure of 1.2 atm increases from 1.0L to 4.0L. What is the final presure of the gas assuming constant temperature.

Respuesta :

using the formula
V1P1=V2P2
where V1=1.0
V2=4.0
P1=1.2
P2=?
P2=V1P1/V2
P2=1.0*1.2/4.0
P2=0.3 atm

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