Answer:
OPTION B) 2ab
Step-by-step explanation:
Given:
Side of larger square = (a + b) units
Side of smaller square = c units
To Find:
The area of all four triangles combined = ?
Solution:
a^2 + b^2 = c^2 (Pythagoras theorem) -(1)
The area of all four triangles combined = Area of larger square - Area of smaller square
The area of all four triangles combined = (a + b)^2 - c^2
The area of all four triangles combined = a^2 + b^2 + 2ab - (a^2 + b^2) {By (1)}
The area of all four triangles combined = a^2 + b^2 + 2ab - a^2 - b^2
The area of all four triangles combined = a^2 - a^2 + b^2 - b^2 + 2ab
Therefore, The area of all four triangles combined = 2ab sq. units
OPTION B) 2ab
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