Which of the following functions would not model exponential decay?o A) h (x) 44 0.89O B) j (x) (0.34O C) b(x) 876 (1)o D z(x)- 7 (0.999)4x-2

Answer:
[tex]b(x) = 875(1)^x[/tex]
Step-by-step explanation:
An exponential function [tex]y=ab^x[/tex] is called,
(i) Growth function : If 1 < b,
(ii) Decay function : If 0 < b < 1
[tex]h(x) = 44(0.89)^{2x}[/tex]
[tex]\implies h(x) = 44(0.89^2)^2 = 44(0.7921)^x[/tex]
∵ 0.7921 < 1
Hence, it is a decay function,
[tex]j(x) = (0.34)^{x-3}= (0.34)^{-3} (0.34)^x\implies j(x) =25.44(0.34)^x[/tex]
∵ 0.34 < 1
Hence, j(x) is a decay function,
[tex]b(x) = 875(1)^x \implies b(x) =875[/tex]
Which is a constant function,
Hence, b(x) is not an exponential decay function.
[tex]z(x) = 7(0.999)^{4x-2}=7(0.999)^{-2} (0.999)^x=7.014(0.999)^x[/tex]
∵ 0.999 < 1
Hence, z(x) is a decay function.