Which of the following functions would not model exponential decay?o A) h (x) 44 0.89O B) j (x) (0.34O C) b(x) 876 (1)o D z(x)- 7 (0.999)4x-2

Which of the following functions would not model exponential decayo A h x 44 089O B j x 034O C bx 876 1o D zx 7 09994x2 class=

Respuesta :

caylus
Hello,
1^x=1
==>b(x)=876 is not a model exponential.

Answer C

Answer:

[tex]b(x) = 875(1)^x[/tex]

Step-by-step explanation:

An exponential function [tex]y=ab^x[/tex] is called,

(i) Growth function : If 1 < b,

(ii) Decay function : If 0 < b < 1

[tex]h(x) = 44(0.89)^{2x}[/tex]

[tex]\implies h(x) = 44(0.89^2)^2 = 44(0.7921)^x[/tex]

∵ 0.7921 < 1

Hence, it is a decay function,

[tex]j(x) = (0.34)^{x-3}= (0.34)^{-3} (0.34)^x\implies j(x) =25.44(0.34)^x[/tex]

∵ 0.34 < 1

Hence, j(x) is a decay function,

[tex]b(x) = 875(1)^x \implies b(x) =875[/tex]

Which is a constant function,

Hence, b(x) is not an exponential decay function.

[tex]z(x) = 7(0.999)^{4x-2}=7(0.999)^{-2} (0.999)^x=7.014(0.999)^x[/tex]

∵ 0.999 < 1

Hence, z(x) is a decay function.