Answer:
The point-slope form of the line is y - 3 = -2(x + 2)
Step-by-step explanation:
The point-slope form of the equation of a line is
y - y1 = m(x - x1), where
- (x1, y1) is a point on the line
- m is the slope of the line
The rule of the slope is [tex]m=\frac{y2-y1}{x2-x1}[/tex] , where
- (x1, y1) and (x2, y2) are two points on the line.
Let us use these rules to solve the question
∵ (-2, 3) and (0, -1) are two points on the line
∴ x1 = -2 and y1 = 3
∴ x2 = 0 and y2 = -1
→ Substitute them in the rule of the slope to find it
∵ m = [tex]\frac{-1-3}{0--2}=\frac{-4}{0+2}=\frac{-4}{2}=-2[/tex]
∴ m = -2
→ Substitute the value of m and point (-2, 3) in the form of the
equation above
∵ m = -2 and (x1, y1) = (-2, 3)
∴ y - 3 = -2(x - -2)
→ Remember (-)(-) = (+)
∴ y - 3 = -2(x + 2)
∴ The point-slope form of the line is y - 3 = -2(x + 2)
