Answer:
The 35-watt light bulb does a work of 46200 joules in 1320 seconds.
Explanation:
From Physics we remember the definition of work ([tex]W[/tex]), measured in joules, by the following integral equation:
[tex]W = \int\limits_{0}^{t} {\dot W} \, dt[/tex] (1)
Where [tex]\dot W[/tex] is the power, measured in watts.
If the power is stable in time, then the work can be calculated by the following algebraic equation:
[tex]W = \dot{W}\cdot \Delta t[/tex] (2)
If we know that [tex]\dot W = 35\,W[/tex] and [tex]\Delta t = 1320\,s[/tex], then the work done by the 35-light bulb is:
[tex]W = (35\,W)\cdot (1320\,s)[/tex]
[tex]W = 46200\,J[/tex]
The 35-watt light bulb does a work of 46200 joules in 1320 seconds.
