The length of the rectangle is [tex]\rm x(x-3)[/tex].
Given
The area of the rectangle = [tex]\rm x^3+3x^2-18x[/tex] square inches
The width of the rectangle = x + 6 inches
Area of the rectangle
The area of the rectangle is equal to the product of length and width of the rectangle.
Let the length of the rectangle be L.
The area of the rectangle is given by;
[tex]\rm Area \ of \ the \ rectangle =Length \times Width\\\\[/tex]
Substitute all the values in the formula;
[tex]\rm Area \ of \ the \ rectangle =Length \times Width\\\\\rm x^3+3x^2-18x= L \times (x+6)\\\\L=\dfrac{ x^3+3x^2-18x}{x+6}\\\\L = \dfrac{ x(x+6)(x-3)}{x+6}\\\\ L = x (x-3)[/tex]
Hence, the length of the rectangle is [tex]\rm x(x-3)[/tex].
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https://brainly.com/question/14383947
