The quadratic equation cannonball’s path if it was launched with the same velocity, but from the ground instead would be given by:
[tex]h(t) = -4.9t^2 + 19.8t[/tex]
What is the quadratic equation for the height of a projectile?
Considering the gravity, it is modeled by:
[tex]h(t) = -4.9t^2 + v_0t + h_0[/tex]
In which:
- [tex]v_0[/tex] is the initial velocity.
- [tex]h_0[/tex] is the initial height.
For this problem, we want:
- The same initial velocity, hence [tex]v_0 = 19.8[/tex].
- Launched from the ground, hence [tex]h_0 = 0[/tex].
Then, the equation is:
[tex]h(t) = -4.9t^2 + 19.8t[/tex]
More can be learned about quadratic equations at https://brainly.com/question/24737967
