Can someone help me with question 2?
1.Weighed out 0.215 g of Cu(NO3)2•3H2O into a 50.00 mL volumetric flask and
diluted to the line using 0.25 M NH. How many moles of Cu(NO3)2-3H20 were added to the flask?
b. How many moles of Cuz* were added to the flask (the mole ratio between
Cu(N03)2•3H20 : Cu^2+ is 1:1)?

C) What is the Molarity of the Cu^2+ solution?

2) The student then transferred 25.00 mL of Solution 1 from above to a 50.00 mL volumetric
flask and diluted to the line using 0.25 M NH3. What is the concentration of this new
solution?

Question

24-01-2024
Chemistry

contestada

Can someone help me with question 2?
1.Weighed out 0.215 g of Cu(NO3)2•3H2O into a 50.00 mL volumetric flask and
diluted to the line using 0.25 M NH. How many moles of Cu(NO3)2-3H20 were added to the flask?
b. How many moles of Cuz* were added to the flask (the mole ratio between
Cu(N03)2•3H20 : Cu^2+ is 1:1)?

C) What is the Molarity of the Cu^2+ solution?

2) The student then transferred 25.00 mL of Solution 1 from above to a 50.00 mL volumetric
flask and diluted to the line using 0.25 M NH3. What is the concentration of this new
solution?

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qhvaughn qhvaughn · Answer 1 · 2024-01-24T23:33:11+01:00

Answer:

a. 0.0015 moles of Cu(NO3)2•3H2O were added to the flask.

b. 0.0015 moles of Cu^2+ were added to the flask.

c. The Molarity of the Cu^2+ solution is 0.03 M.

Explanation:

a. The moles of Cu(NO3)2•3H2O can be calculated using the formula:

Moles = Weight (g) / Molar Mass (g/mol)

Given that the weight of Cu(NO3)2•3H2O is 0.215 g and its molar mass is 187.55 g/mol, we get:

Moles = 0.215 g / 187.55 g/mol ≈ 0.0015 moles

b. Since the mole ratio between Cu(NO3)2•3H2O and Cu^2+ is 1:1, the moles of Cu^2+ are also 0.0015 moles.

c. Molarity (M) is defined as moles of solute per liter of solution. The formula is:

M = Moles of solute / Volume of solution (L)

In this case, the moles of Cu^2+ is 0.0015 moles (as calculated in part b), and the volume of the solution is 0.05 L (50.00 mL converted to liters). Thus,

M = 0.0015 moles / 0.05 L = 0.03 M

Therefore, the Molarity of the Cu^2+ solution is 0.03 M.

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